Table of Contents
PROPOSITION 51 THEOREM 18
If a centripetal force tending on all sides to the centre C of a globe, be in all places as the distance of the place from the centre, and by this force
oscillate (in the manner above de alone acting upon it, the body the in the / say, that all the oscil perimeter of scribed] cycloid how in soever will be performed in equal lations, tfiemselves, unequal QRS ; times. W T infinitely produced let fall the perpendicular CT. and Because the centripetal force with which the body T CX, join towards C is as the distance CT, let this is impelled (by Cor. 2, of the For upon the tangent I ,aws) be resolved into body directly from P the parts CX, TX, of stretches the thread PT, which CX impelling the and by the resistance the rhread makes to it is totally employed, producing no other effect but the 3ther part TX, impelling the body transversely or towards X, directly Then it is plain that the accelera accelerates the motion in the cycloid. ; tion of the body, proportional to this accelerating force, will bo every
moment
WV,
as
and
the length
TX,
TX,
[BOOK
that
is
(because
1
CV
TW proportional to them are given),
TW,
as the length
that is (by Cor. 1, Prop. XLIX)
as the length of the arc of the cycloid TR.
If there
fore two pendulums APT, Apt, be
drawn
unequally
aside from the perpendicular AR, and let fall
together,
their accelerations will be always as the arcs to be de
tR.
But the parts described at the
are as the accelerations, thai
of
the
motion
beginning
are
to be described at the be
that
the
wholes
as
is,
scribed
TR,
ginning, and therefore the parts which remain to be
described, and the subsequent accelerations proportional to those parts, are
also as the wholes, and so on.
Therefore the accelerations, and consequently
the velocities generated, and the parts described with those velocities, and
the parts to be described, are always as the wholes and therefore the parts
to be described
preserving a given ratio to each other will vanish together,
that is, the two bodies oscillating will arrive together at the perpendicular AR.
;
And since on the other hand
the ascent of the pendulums from the lowest place
the
same cycloidal arcs with a retrograde motion, is retarded in
through
the several places they pass through by the same forces by which their de
R
scent
was accelerated
:
it is
plain that the velocities of their ascent and de
and consequently performed in equal
and
two
the
since
and, therefore,
parts of the cycloid
lying
on either side of the perpendicular are similar and equal, the two pendu
lums will perform as well the wholes as the halves of their oscillations in
scent through the
times
same
arcs are equal,
RQ
RS
;
the same times.
Corollary
The force with which the body T is accelerated or retarded in any place T of the cycloid, is to the whole weight of the same body in the highest place S or Q, as the arc of the cycloid TR is to the arc SR or QR
Proposition 50 Theorem 33
Finding the orbits from the focus given
Proposition 52 Problem 34
Finding the orbits from the focus given
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