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    <title>Quantization as an eigenvalue problem on Superphysics</title>
    <link>https://www.superphysics.org/research/schrodinger/quantization/</link>
    <description>Recent content in Quantization as an eigenvalue problem on Superphysics</description>
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      <title>Quantization as an eigenvalue problem</title>
      <link>https://www.superphysics.org/research/schrodinger/quantization/part-1d/</link>
      <pubDate>Mon, 01 Jan 0001 00:00:00 +0000</pubDate>
      <guid>https://www.superphysics.org/research/schrodinger/quantization/part-1d/</guid>
      <description>&lt;ol start=&#34;2&#34;&gt;&#xA;&lt;li&gt;E &amp;lt; 0.&lt;/li&gt;&#xA;&lt;/ol&gt;&#xA;&lt;p&gt;In this case the condition (15) is not eo ipso excluded, but for the&#xA;moment we hold onto its exclusion, as arranged. Then, according to (14′′) and&#xA;(17), U1 grows unlimited for r = ∞, whereas U2 vanishes exponentially. Our entire&#xA;transcendent U (and the same holds true for χ) will then remain finite if and only&#xA;if U is identical to U2, a part from a numerical factor. However, this is not the&#xA;case. One realises this so: choosing in (12) for the integration contour L a closed&#xA;circuit about both the points c1 and c2 (due to the integerness of the sum α1 + α2&#xA;such contour is then really closed on the Riemann surface of the integrand), upon&#xA;fulfillment of the very condition (13), one can easily show that the integral (12)&#xA;represents then our entire transcendent U . Namely, it can be developed in a series&#xA;of positive powers of r, which always converges for sufficiently small values of r,&#xA;hence it satisfies the differential equation (7′), and thus the power series must&#xA;coincide with that for U . So: U is represented by (12) when L is a closed contour&#xA;about both the points c1 and c2. However, this closed contour can be distorted&#xA;so that it appears as the combination of the two previously considered integration paths, those related to U1 and U2, and indeed without vanishing factors, say 1 and&#xA;e2πiα1 . QED17&lt;/p&gt;</description>
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